If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
(x^2-7)/x <= 0
x = 0
(x^2-7)/x <= 0
(x^2-7)/x <= 0
( x )
x+0 <= 0 // - 0
x <= 0
( x^2-7 )
1*x^2 <= 7
1*x^2 <= 7 // : 1
x^2 <= 7/1
x^2 <= 7
x^2 <= 7 // ^ 1/2
abs(x) <= 7^(1/2)
x in <-7^(1/2):7^(1/2)>
(-oo:-7^(1/2)) (-7^(1/2):0) (0:7^(1/2)) (7^(1/2):+oo) x - - + + x^2-7 + - - +
x = 0
x = 0
x in (-7^(1/2):0) U (7^(1/2):+oo)
ln((x^2-7)/x) = 0
ln((x^2-7)/x) = ln(e^0)
(x^2-7)/x = e^0
(x^2-7)/x-e^0 = 0
(x^2-7)/x-1 = 0
(x^2-7)/x+(-1*x)/x = 0
x^2-1*x-7 = 0
x^2-x-7 = 0
x^2-x-7 = 0
x^2-x-7 = 0
DELTA = (-1)^2-(-7*1*4)
DELTA = 29
DELTA > 0
x = (29^(1/2)+1)/(1*2) or x = (1-29^(1/2))/(1*2)
x = (29^(1/2)+1)/2 or x = (1-29^(1/2))/2
(x-((1-29^(1/2))/2))*(x-((29^(1/2)+1)/2)) = 0
((x-((1-29^(1/2))/2))*(x-((29^(1/2)+1)/2)))/x = 0
((x-((1-29^(1/2))/2))*(x-((29^(1/2)+1)/2)))/x = 0 // * x
(x-((1-29^(1/2))/2))*(x-((29^(1/2)+1)/2)) = 0
( x-((1-29^(1/2))/2) )
x-((1-29^(1/2))/2) = 0 // + (1-29^(1/2))/2
x = (1-29^(1/2))/2
( x-((29^(1/2)+1)/2) )
x-((29^(1/2)+1)/2) = 0 // + (29^(1/2)+1)/2
x = (29^(1/2)+1)/2
x in { (1-29^(1/2))/2, (29^(1/2)+1)/2 }
| -5+7b=1+7b-5 | | 5x+3=15x-93 | | 1+5n+5n=11 | | 5x-3=15x-9 | | 1n+2=-16n+(14n+2n) | | 1+5n+5n= | | 16=w/7 | | 3sinx-2=1 | | -3r-11=-4r-4 | | 7x^2=-12 | | -2x+17y=-7 | | 7(2p-4)=10p | | Xcm+6xcm+11xcm=32cm | | 29=-4x+9 | | 3t^3+4t^2-5t-2=0 | | 1-n=-3-2n | | X-130/26 | | 2/d=8/2 | | (22-x)(x-13)=0 | | 3m^3-8m^3/6m^2-4m^2= | | -1.5t-0.83=0.44 | | 9+3n-8=8n+6-4n | | 2-3y=7 | | x-5+4x=5 | | 3y-8=31 | | 7e^2x+5=61 | | -1.5t-8.33=0.44 | | 24/2=6/h | | -2z-2-4z=3-2z | | 5x-8y=-14 | | 3a^2-7=53 | | 4(3x+8)+6= |